(X+4)(x-2)=x^2+20

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Solution for (X+4)(x-2)=x^2+20 equation: 



(X+4)(X-2)=X^2+20

We move all terms to the left:

(X+4)(X-2)-(X^2+20)=0

We get rid of parentheses

-X^2+(X+4)(X-2)-20=0

We multiply parentheses ..

-X^2+(+X^2-2X+4X-8)-20=0

We add all the numbers together, and all the variables

-1X^2+(+X^2-2X+4X-8)-20=0

We get rid of parentheses

-1X^2+X^2-2X+4X-8-20=0

We add all the numbers together, and all the variables

2X-28=0

We move all terms containing X to the left, all other terms to the right

2X=28

X=28/2

X=14

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